If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2.7t^2+50t-3.5=0
a = 2.7; b = 50; c = -3.5;
Δ = b2-4ac
Δ = 502-4·2.7·(-3.5)
Δ = 2537.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-\sqrt{2537.8}}{2*2.7}=\frac{-50-\sqrt{2537.8}}{5.4} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+\sqrt{2537.8}}{2*2.7}=\frac{-50+\sqrt{2537.8}}{5.4} $
| -75=5n | | 9-2s=s | | 3=7-3(x+3) | | 7(1+12n)=427 | | 3x-12=-9x+24 | | 2+7p=5p+8 | | c(7)-c(3)=32 | | -36=-18+n | | 2c=3c-5 | | 5−2x/5+x−4/10=9/10 | | 12-3x+5x=3(x-2) | | 20=m/6 | | 6b-2(2b+16)=-24 | | 3(y+8)=2(10+3/2y) | | 16+r=21 | | 3-(c-5)+6c=11 | | 2n+6=5n–6 | | -3b+8(b+2=-19 | | -874=-3(7x+1)-4 | | -3n+33=-6(n-2) | | 4s+8=3+54s | | -27a=-459 | | 2-2*(x+4)+3=3 | | 7x-4+2×=52-5× | | 27+8x-1=90 | | X2+5x=2x-12 | | -27=n/9 | | 2n–7=8–3n | | -13=-21+x | | 3x+4+2x+6=80 | | 28-5=2+3=(x+3) | | 37=20-n |